119=r^2

Solution for 119=r^2 equation:

119=r^2

We move all terms to the left:

119-(r^2)=0

We add all the numbers together, and all the variables

-1r^2+119=0

a = -1; b = 0; c = +119;
Δ = b2-4ac
Δ = 02-4·(-1)·119
Δ = 476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{476}=\sqrt{4*119}=\sqrt{4}*\sqrt{119}=2\sqrt{119}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{119}}{2*-1}=\frac{0-2\sqrt{119}}{-2}
=-\frac{2\sqrt{119}}{-2}
=-\frac{\sqrt{119}}{-1}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{119}}{2*-1}=\frac{0+2\sqrt{119}}{-2}
=\frac{2\sqrt{119}}{-2}
=\frac{\sqrt{119}}{-1}
$